MCQ on Oxidation Number and Oxidation State: Chemistry is considered to be the most scoring subject in NEET JEE Exam. As it is one of the easiest scoring subjects, it is often ignored and undermined a subject. But if you want to get an edge over others, here is a tip, master NEET/JEE Chemistry concepts. Chemistry demands the attention of students in understanding reactions and concrete basic understanding but once done it only gets easier from there. Mastering NCERT syllabus for NEET/JEE Chemistry should be topping your list of to-do for chemistry.

In this post we are providing you MCQ on Oxidation Number and Oxidation State, which will be beneficial for you in upcoming NEET, JEE, Medical and Engineering Exams.

MCQ on Oxidation Number and Oxidation State

Q1. What is the oxidation number of chlorine in HClO₄?
a) +3
b) +5
c) +7
d) +9

Q2. The products formed when an aqueous solution of NaBr is electrolysed in a cell having inert electrodes are _______.
a) Na and Br₂
b) Na and O₂
c) H₂ and O₂
d) H₂, Br₂, NaOH

Q3. The oxidation state of each Cl in CaOCl₂ is _______.
a) 0
b) -1
c) +1
d) +1, -1

Q4. The oxidation number of carbon in CH₂Cl₂ is _______.
a) 0
b) 2
c) 3
d) 5

Q5. What products are expected from the disproportionation reaction of hypochlorous acid?
a) HCl and Cl₂O
b) HCl and HClO₃
c) HClO₃ and Cl₂O
d) HClO₂ and HClO₄

Q6.  Number of moles of MnO₄^– required to oxidise one mole of ferrous oxalate completely in the acidic medium will be _______.
a) 0.2 moles
b) 0.4 moles
c) 0.6 moles
d) 0.8 moles

Q7. Which of the following will not be oxidised by O₃?
a) KI
b) FeSO₄
c) KMnO₄
d) K₂MnO₄

Q8. Number of moles of K₂Cr₂O₇ reduced by 1 mole of Sn²⁺ is _______.
a) 1
b) 1/3
c) 1/6
d) 1/8

Q9. Which of the following elements does not show disproportionation tendency?
a) F
b) J
c) Cl
d) Br

Q10. The oxidation state of chromium in the final product formed by the reaction between KI and acidified potassium dichromate solution is _______.
a) +2
b) +3
c) +4
d) +5

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