Short Trick to find Bond Order – Chemistry Mnemonics

Short Trick to find Bond Order: Notes preparation is necessary for the students for the preparation of National Eligibility cum Entrance Examination (NEET). The exam is common test exam conducted for the students to take admission in medical colleges. The students who have studied biology as subject in science stream can apply for the exam and start their preparation for the exam. Students can check Short Tricks, notes, syllabus, mock test here at 

Short Trick to find Bond Order

These Short Tricks (Mnemonics) on Short Trick to find Bond Order are very helpful for various Medical Entrance Exam like NEET, AIIMS, JIPMER, PGIMER, CBSE Board, ICSE Board, Class 12th, 11th. Here are some mnemonic of this chapter topics listed below. These are very helpful for class 11th and 12th students :-

Short Trick to find Bond Order

Bond order shows the bond(number of chemicals) that are present between pair of atoms.
FORMULA :- 1/2 [Nb – Na]
Na = number of antibonding electrons
Nb = number of bonding electrons
How to find bond order?
Follow these simple steps to get the bond order of any of the elements:-
 Step 1 

First, you have to find the no. of electrons in a given compound or molecule. For example:-
The question is to find the bond order of N2 
Then no. of electrons in this molecule is 7+7 = 14
Similarly, for CN- compound, it will be 6+7+1 = 14; for F2 it will be 9+9= 18.

 Step 2 

After adding no. of electron, you will get numbers   like 10,11,12,13,14,15,16….etc. 

Now, remember this table- 

No. of electrons    Bond Order 
10              –            1
11              –            1.5
12             –             2
13             –            2.5
14             –             3
15             –            2.5
16             –             2
17             –             1.5
18             –              1

It shows that if you get no. of electrons as 14 then bond order will be 3, Similarly for 13 bond order will be 2.5

It means you have to subtract 0.5 in going up and down by 14 electrons for one step.

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