Magnetic Field on the Axis of a Circular Current Loop – Class 12 | Chapter – 4 | Physics Short Notes Series PDF for NEET & JEE

Magnetic Field on the Axis of a Circular Current Loop: The magnetic field on the axis of a circular current loop can be calculated using the Biot-Savart Law. The Biot-Savart Law states that the magnetic field at a point P due to a current element dI is given by:

dΒ = μ0/(4π) * (I * dl × r)/r³

where,

• μ0 is the permeability of free space,
• I is the current in the loop,
• dl is a small element of the current-carrying wire, and
• r is the distance from the point P to the current element dI.

Magnetic Field on the Axis of a Circular Current Loop

To calculate the magnetic field on the axis of a circular current loop, we need to integrate the magnetic field due to each small element of the loop over the entire loop. This can be done using the following expression:

Β = μ0/(4π) * ∫(I * dl × r)/r³

where the integral is taken over the entire loop.

The magnetic field on the axis of a circular current loop is proportional to the current in the loop and inversely proportional to the radius of the loop. The magnetic field also depends on the orientation of the loop relative to the point P, with the field being strongest when the loop is perpendicular to the axis and weakest when the loop is parallel to the axis.

---

JOIN OUR TELEGRAM CHANNELS
Biology Quiz & Notes	Physics Quiz & Notes	Chemistry Quiz & Notes

---

Follow on Facebook

By Team Learning Mantras