Acceleration Due to Gravity of the Earth – Class 11 | Chapter – 8 | Physics Short Notes Series PDF for NEET & JEE

Acceleration Due to Gravity of the Earth: The acceleration due to gravity of the Earth is the acceleration experienced by an object in the Earth’s gravitational field. This acceleration is denoted by the symbol “g” and has an approximate value of 9.81 m/s2. The acceleration due to gravity is a vector quantity, and it points towards the center of the Earth.

The value of the acceleration due to gravity varies depending on the location and altitude on the Earth’s surface. It is slightly less at the equator than at the poles due to the centrifugal force caused by the Earth’s rotation. At higher altitudes, the acceleration due to gravity decreases slightly due to the decrease in the Earth’s gravitational field.

The acceleration due to gravity of the Earth is an important parameter in many areas of science and technology. It is used in the design of buildings, bridges, and other structures to ensure that they can withstand the gravitational forces acting on them. It is also used in many experiments and measurements, such as determining the mass of an object using a balance, or measuring the acceleration of a falling object.

Formula of  Acceleration Due to Gravity of the Earth

Acceleration Due to Gravity (g)
Symbol g
Dimensional Formula M0L1T-2
SI Unit ms-2
Formula g = GM/r2
Values of g in SI 9.806 ms-2
Values of g in CGS 980 cm s-2

Force acting on a body due to gravity is given by, f = mg

Where f is the force acting on the body, g is the acceleration due to gravity, m is mass of the body.

According to the universal law of gravitation, f = GmM/(r+h)2

Where,

  • f = force between two bodies,
  • G = universal gravitational constant (6.67×10-11 Nm2/kg2)
  • m = mass of the object,
  • M = mass of the earth,
  • r = radius of the earth.
  • h = height at which the body is from the surface of the earth.

As the height (h) is negligibly small compared to the radius of the earth we re-frame the equation as follows,

f = GmM/r2

Now equating both the expressions,

mg = GmM/r2

⇒ g = GM/r2

Therefore, the formula of acceleration due to gravity is given by, g = GM/r2

Note: It depends on the mass and radius of the earth.

 


JOIN OUR TELEGRAM CHANNELS
Biology Quiz & Notes Physics Quiz & Notes Chemistry Quiz & Notes

Follow on Facebook

By Team Learning Mantras

Admin

Recent Posts

TNPSC Civil Services Exam Notification (Group-IV) 2024: Official Notifications | Exam Dates | Exam Pattern | Syllabus | Mock Test Papers | Study Materials & Results

TNPSC Civil Services Exam Notification: The Tamil Nadu Public Service Commission (TNPSC) has Announced Notification…

3 months ago

Best Books for RRB Technician Exam: Latest Books for RRB Technician Exam 2024

Best Books for RRB Technician Exam: The Railway Recruitment Board conducts the RRB Technician Exams.…

3 months ago

RRB Technician Result: Check Your RRB Technician Exam Result 2024 Now (Link to be Activated)

RRB Technician Result: The Railway Recruitment Board announces the RRB Technician Result within a month…

3 months ago

RRB Technician Admit Card: Download RRB Technician 2024 Admit Card Now (Link to be Activated)

RRB Technician Admit Card: The Railway Technician Admit Card will be released by the Railway…

3 months ago

RRB Technician Salary Structure 2024: RRB Technician in Hand Salary, Perks, Allowances, Job Profile

RRB Technician Salary: The RRB Technician Grade Pay is 1900 and Basic pay is 19900+HRA…

3 months ago

RRB Technician Study Materials: Get Best and Free Study Materials PDF for RRB Technician Exam 2024

RRB Technician Study Materials: The Railway Recruitment Board conducts the RRB Technician Exams. Government of India,…

3 months ago

This website uses cookies.